Optimal. Leaf size=194 \[ \frac {2 d^3 \left (a+b \log \left (c x^n\right )\right )}{e^4 \sqrt {d+e x}}+\frac {6 d^2 \sqrt {d+e x} \left (a+b \log \left (c x^n\right )\right )}{e^4}-\frac {2 d (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{e^4}+\frac {2 (d+e x)^{5/2} \left (a+b \log \left (c x^n\right )\right )}{5 e^4}+\frac {64 b d^{5/2} n \tanh ^{-1}\left (\frac {\sqrt {d+e x}}{\sqrt {d}}\right )}{5 e^4}-\frac {44 b d^2 n \sqrt {d+e x}}{5 e^4}+\frac {16 b d n (d+e x)^{3/2}}{15 e^4}-\frac {4 b n (d+e x)^{5/2}}{25 e^4} \]
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Rubi [A] time = 0.20, antiderivative size = 194, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.261, Rules used = {43, 2350, 12, 1620, 63, 208} \[ \frac {2 d^3 \left (a+b \log \left (c x^n\right )\right )}{e^4 \sqrt {d+e x}}+\frac {6 d^2 \sqrt {d+e x} \left (a+b \log \left (c x^n\right )\right )}{e^4}-\frac {2 d (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{e^4}+\frac {2 (d+e x)^{5/2} \left (a+b \log \left (c x^n\right )\right )}{5 e^4}-\frac {44 b d^2 n \sqrt {d+e x}}{5 e^4}+\frac {64 b d^{5/2} n \tanh ^{-1}\left (\frac {\sqrt {d+e x}}{\sqrt {d}}\right )}{5 e^4}+\frac {16 b d n (d+e x)^{3/2}}{15 e^4}-\frac {4 b n (d+e x)^{5/2}}{25 e^4} \]
Antiderivative was successfully verified.
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Rule 12
Rule 43
Rule 63
Rule 208
Rule 1620
Rule 2350
Rubi steps
\begin {align*} \int \frac {x^3 \left (a+b \log \left (c x^n\right )\right )}{(d+e x)^{3/2}} \, dx &=\frac {2 d^3 \left (a+b \log \left (c x^n\right )\right )}{e^4 \sqrt {d+e x}}+\frac {6 d^2 \sqrt {d+e x} \left (a+b \log \left (c x^n\right )\right )}{e^4}-\frac {2 d (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{e^4}+\frac {2 (d+e x)^{5/2} \left (a+b \log \left (c x^n\right )\right )}{5 e^4}-(b n) \int \frac {2 \left (16 d^3+8 d^2 e x-2 d e^2 x^2+e^3 x^3\right )}{5 e^4 x \sqrt {d+e x}} \, dx\\ &=\frac {2 d^3 \left (a+b \log \left (c x^n\right )\right )}{e^4 \sqrt {d+e x}}+\frac {6 d^2 \sqrt {d+e x} \left (a+b \log \left (c x^n\right )\right )}{e^4}-\frac {2 d (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{e^4}+\frac {2 (d+e x)^{5/2} \left (a+b \log \left (c x^n\right )\right )}{5 e^4}-\frac {(2 b n) \int \frac {16 d^3+8 d^2 e x-2 d e^2 x^2+e^3 x^3}{x \sqrt {d+e x}} \, dx}{5 e^4}\\ &=\frac {2 d^3 \left (a+b \log \left (c x^n\right )\right )}{e^4 \sqrt {d+e x}}+\frac {6 d^2 \sqrt {d+e x} \left (a+b \log \left (c x^n\right )\right )}{e^4}-\frac {2 d (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{e^4}+\frac {2 (d+e x)^{5/2} \left (a+b \log \left (c x^n\right )\right )}{5 e^4}-\frac {(2 b n) \int \left (\frac {11 d^2 e}{\sqrt {d+e x}}+\frac {16 d^3}{x \sqrt {d+e x}}-4 d e \sqrt {d+e x}+e (d+e x)^{3/2}\right ) \, dx}{5 e^4}\\ &=-\frac {44 b d^2 n \sqrt {d+e x}}{5 e^4}+\frac {16 b d n (d+e x)^{3/2}}{15 e^4}-\frac {4 b n (d+e x)^{5/2}}{25 e^4}+\frac {2 d^3 \left (a+b \log \left (c x^n\right )\right )}{e^4 \sqrt {d+e x}}+\frac {6 d^2 \sqrt {d+e x} \left (a+b \log \left (c x^n\right )\right )}{e^4}-\frac {2 d (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{e^4}+\frac {2 (d+e x)^{5/2} \left (a+b \log \left (c x^n\right )\right )}{5 e^4}-\frac {\left (32 b d^3 n\right ) \int \frac {1}{x \sqrt {d+e x}} \, dx}{5 e^4}\\ &=-\frac {44 b d^2 n \sqrt {d+e x}}{5 e^4}+\frac {16 b d n (d+e x)^{3/2}}{15 e^4}-\frac {4 b n (d+e x)^{5/2}}{25 e^4}+\frac {2 d^3 \left (a+b \log \left (c x^n\right )\right )}{e^4 \sqrt {d+e x}}+\frac {6 d^2 \sqrt {d+e x} \left (a+b \log \left (c x^n\right )\right )}{e^4}-\frac {2 d (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{e^4}+\frac {2 (d+e x)^{5/2} \left (a+b \log \left (c x^n\right )\right )}{5 e^4}-\frac {\left (64 b d^3 n\right ) \operatorname {Subst}\left (\int \frac {1}{-\frac {d}{e}+\frac {x^2}{e}} \, dx,x,\sqrt {d+e x}\right )}{5 e^5}\\ &=-\frac {44 b d^2 n \sqrt {d+e x}}{5 e^4}+\frac {16 b d n (d+e x)^{3/2}}{15 e^4}-\frac {4 b n (d+e x)^{5/2}}{25 e^4}+\frac {64 b d^{5/2} n \tanh ^{-1}\left (\frac {\sqrt {d+e x}}{\sqrt {d}}\right )}{5 e^4}+\frac {2 d^3 \left (a+b \log \left (c x^n\right )\right )}{e^4 \sqrt {d+e x}}+\frac {6 d^2 \sqrt {d+e x} \left (a+b \log \left (c x^n\right )\right )}{e^4}-\frac {2 d (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{e^4}+\frac {2 (d+e x)^{5/2} \left (a+b \log \left (c x^n\right )\right )}{5 e^4}\\ \end {align*}
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Mathematica [A] time = 0.13, size = 159, normalized size = 0.82 \[ \frac {480 a d^3+240 a d^2 e x-60 a d e^2 x^2+30 a e^3 x^3+30 b \left (16 d^3+8 d^2 e x-2 d e^2 x^2+e^3 x^3\right ) \log \left (c x^n\right )+960 b d^{5/2} n \sqrt {d+e x} \tanh ^{-1}\left (\frac {\sqrt {d+e x}}{\sqrt {d}}\right )-592 b d^3 n-536 b d^2 e n x+44 b d e^2 n x^2-12 b e^3 n x^3}{75 e^4 \sqrt {d+e x}} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.50, size = 435, normalized size = 2.24 \[ \left [\frac {2 \, {\left (240 \, {\left (b d^{2} e n x + b d^{3} n\right )} \sqrt {d} \log \left (\frac {e x + 2 \, \sqrt {e x + d} \sqrt {d} + 2 \, d}{x}\right ) - {\left (296 \, b d^{3} n - 240 \, a d^{3} + 3 \, {\left (2 \, b e^{3} n - 5 \, a e^{3}\right )} x^{3} - 2 \, {\left (11 \, b d e^{2} n - 15 \, a d e^{2}\right )} x^{2} + 4 \, {\left (67 \, b d^{2} e n - 30 \, a d^{2} e\right )} x - 15 \, {\left (b e^{3} x^{3} - 2 \, b d e^{2} x^{2} + 8 \, b d^{2} e x + 16 \, b d^{3}\right )} \log \relax (c) - 15 \, {\left (b e^{3} n x^{3} - 2 \, b d e^{2} n x^{2} + 8 \, b d^{2} e n x + 16 \, b d^{3} n\right )} \log \relax (x)\right )} \sqrt {e x + d}\right )}}{75 \, {\left (e^{5} x + d e^{4}\right )}}, -\frac {2 \, {\left (480 \, {\left (b d^{2} e n x + b d^{3} n\right )} \sqrt {-d} \arctan \left (\frac {\sqrt {e x + d} \sqrt {-d}}{d}\right ) + {\left (296 \, b d^{3} n - 240 \, a d^{3} + 3 \, {\left (2 \, b e^{3} n - 5 \, a e^{3}\right )} x^{3} - 2 \, {\left (11 \, b d e^{2} n - 15 \, a d e^{2}\right )} x^{2} + 4 \, {\left (67 \, b d^{2} e n - 30 \, a d^{2} e\right )} x - 15 \, {\left (b e^{3} x^{3} - 2 \, b d e^{2} x^{2} + 8 \, b d^{2} e x + 16 \, b d^{3}\right )} \log \relax (c) - 15 \, {\left (b e^{3} n x^{3} - 2 \, b d e^{2} n x^{2} + 8 \, b d^{2} e n x + 16 \, b d^{3} n\right )} \log \relax (x)\right )} \sqrt {e x + d}\right )}}{75 \, {\left (e^{5} x + d e^{4}\right )}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b \log \left (c x^{n}\right ) + a\right )} x^{3}}{{\left (e x + d\right )}^{\frac {3}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.37, size = 0, normalized size = 0.00 \[ \int \frac {\left (b \ln \left (c \,x^{n}\right )+a \right ) x^{3}}{\left (e x +d \right )^{\frac {3}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 1.26, size = 200, normalized size = 1.03 \[ -\frac {4}{75} \, b n {\left (\frac {120 \, d^{\frac {5}{2}} \log \left (\frac {\sqrt {e x + d} - \sqrt {d}}{\sqrt {e x + d} + \sqrt {d}}\right )}{e^{4}} + \frac {3 \, {\left (e x + d\right )}^{\frac {5}{2}} - 20 \, {\left (e x + d\right )}^{\frac {3}{2}} d + 165 \, \sqrt {e x + d} d^{2}}{e^{4}}\right )} + \frac {2}{5} \, b {\left (\frac {{\left (e x + d\right )}^{\frac {5}{2}}}{e^{4}} - \frac {5 \, {\left (e x + d\right )}^{\frac {3}{2}} d}{e^{4}} + \frac {15 \, \sqrt {e x + d} d^{2}}{e^{4}} + \frac {5 \, d^{3}}{\sqrt {e x + d} e^{4}}\right )} \log \left (c x^{n}\right ) + \frac {2}{5} \, a {\left (\frac {{\left (e x + d\right )}^{\frac {5}{2}}}{e^{4}} - \frac {5 \, {\left (e x + d\right )}^{\frac {3}{2}} d}{e^{4}} + \frac {15 \, \sqrt {e x + d} d^{2}}{e^{4}} + \frac {5 \, d^{3}}{\sqrt {e x + d} e^{4}}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {x^3\,\left (a+b\,\ln \left (c\,x^n\right )\right )}{{\left (d+e\,x\right )}^{3/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 56.70, size = 384, normalized size = 1.98 \[ \frac {\frac {2 a d^{3}}{\sqrt {d + e x}} + 6 a d^{2} \sqrt {d + e x} - 2 a d \left (d + e x\right )^{\frac {3}{2}} + \frac {2 a \left (d + e x\right )^{\frac {5}{2}}}{5} - 2 b d^{3} \left (\frac {2 n \operatorname {atan}{\left (\frac {\sqrt {d + e x}}{\sqrt {- d}} \right )}}{\sqrt {- d}} - \frac {\log {\left (c \left (- \frac {d}{e} + \frac {d + e x}{e}\right )^{n} \right )}}{\sqrt {d + e x}}\right ) + 6 b d^{2} \left (\sqrt {d + e x} \log {\left (c \left (- \frac {d}{e} + \frac {d + e x}{e}\right )^{n} \right )} - \frac {2 n \left (\frac {d e \operatorname {atan}{\left (\frac {\sqrt {d + e x}}{\sqrt {- d}} \right )}}{\sqrt {- d}} + e \sqrt {d + e x}\right )}{e}\right ) - 6 b d \left (\frac {\left (d + e x\right )^{\frac {3}{2}} \log {\left (c \left (- \frac {d}{e} + \frac {d + e x}{e}\right )^{n} \right )}}{3} - \frac {2 n \left (\frac {d^{2} e \operatorname {atan}{\left (\frac {\sqrt {d + e x}}{\sqrt {- d}} \right )}}{\sqrt {- d}} + d e \sqrt {d + e x} + \frac {e \left (d + e x\right )^{\frac {3}{2}}}{3}\right )}{3 e}\right ) + 2 b \left (\frac {\left (d + e x\right )^{\frac {5}{2}} \log {\left (c \left (- \frac {d}{e} + \frac {d + e x}{e}\right )^{n} \right )}}{5} - \frac {2 n \left (\frac {d^{3} e \operatorname {atan}{\left (\frac {\sqrt {d + e x}}{\sqrt {- d}} \right )}}{\sqrt {- d}} + d^{2} e \sqrt {d + e x} + \frac {d e \left (d + e x\right )^{\frac {3}{2}}}{3} + \frac {e \left (d + e x\right )^{\frac {5}{2}}}{5}\right )}{5 e}\right )}{e^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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